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SQL Query question...

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SQL Query question... SQL forums discussing structured query language related questions that are platform independent. Discussions include advanced topics such as joins, stored procedures, and triggers.

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  #1  
Old June 15th, 2004, 04:52 PM
LilMoke LilMoke is offline
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Cool SQL Query question...
Hello,

I am trying to do a query on the data below and produce the following report:

Win 95 5
Win 98 8
Win NT 4.0 3
Win NT 5.0 9
Win NT 5.2 20

I am not quite sure how to do a query that contains all the counts. I can do this:

SELECT COUNT(*) FROM dbo.Log WHERE [logField] LIKE '%User Agent:%Windows 95%'

And that works, but I am not sure how to do it for all the platforms. The other caveat is that
the data type is ntext, so I think I need to do something like:

SELECT SUBSTRING(text, 0, 128) AS Expr1, COUNT(*) etc.

I am not an expert at SQL, but understand it well enough to do somewhat complex queries, but
this one has me stumped.

Any help would be greatly appreciated.

The field format:

User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705; .NET CLR 1.1.4322)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705; .NET CLR 1.1.4322)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705; .NET CLR 1.1.4322)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705; .NET CLR 1.1.4322)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0; (R1 1.5))
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0; (R1 1.5))
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0; (R1 1.5))
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98; Win 9x 4.90)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98; Win 9x 4.90)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705; .NET CLR 1.1.4322)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705; .NET CLR 1.1.4322)
User Agent: Mozilla/5.0
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 5.5; Windows 95; Supplied by blueyonder)
User Agent: Mozilla/4.0 (compatible; MSIE 5.5; Windows 95; Supplied by blueyonder)
User Agent: Mozilla/4.0 (compatible; MSIE 5.5; Windows 95; Supplied by blueyonder)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98; GTE_IE4; Hotbar 3.0)
User Agent: Mozilla/4.0 (compatible; MSIE 5.5; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 5.5; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 5.13; Mac_PowerPC)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98; libero)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)
User Agent: Mozilla/4.0 (compatible; MSIE 5.0; Windows 98; DigExt)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)
User Agent: Mozilla/4.0 (compatible; MSIE 5.01; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98)
User Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows 98; (atfile.com))

Thank you,
Tony
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  #2  
Old June 15th, 2004, 06:21 PM
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Memnoch Memnoch is offline
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You should split the value first to retrieve the OS, then insert that into a different field, then your select statement would be something like this
Code:
SELECT OS, COUNT(*) As 'Count'
FROM TableName
GROUP BY OS
ORDER BY 'Count' DESC
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Old June 16th, 2004, 02:06 AM
LilMoke LilMoke is offline
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Yes, that is one option I thought of. However, I already have this data in a table and it contains
thousands of records. Rather than writing code to 'fix-up' the already existing records, I was
hoping I could perform an SQL query to do the job.

Any other ideas/options?

Thanks for your assistance,
Tony
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Old June 16th, 2004, 10:23 AM
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What you could do is create another field called OS.
Extract the OS from the text string and update the OS field with the extracted value, then do a distinct count on that field.
Last edited by Memnoch : June 16th, 2004 at 10:26 AM.
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