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help on functions

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  #1  
Old April 27th, 2005, 05:53 PM
Kudo_Shiho Kudo_Shiho is offline
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Question help on functions
Hi, I'm trying to write a function in my code for VB.net and I have a problem which I hope someone can help me in.
Code:
iTotalDaily = ComputeDailyCost(iDays, iDailyCost)
     iTotalMile = ComputeMileCost(iMile, iMileCost)
     
     Private Function ComputeDailyCost(ByVal a As Integer,_
   				     ByVal b As Integer)
     	Dim iResult As Integer
     	iResult = a * b
     	Return iResult
     
     End Function
     Private Function ComputeMileCost(ByVal a As Integer,_
   				    ByVal b As Integer)
     	Dim iResult As Integer
     	iResult = a * b
     	Return iResult
     
     End Function

There is a message that says that the ComputeDailyCost and ComputeMileCost for the first part is not declared. I'm not sure how I declare the ComputeDailyCost and ComputeMileCost so I was wondering if anyone can help me. Thank you.
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  #2  
Old April 28th, 2005, 03:06 AM
Marc Van Beeume Marc Van Beeume is offline
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I'm not a dot net but a VB6 programmer. According to what i know the code should be as follows in VB6. The name of the variable that returns the value is the same as the name of the function. No need to declare a supplemental variable.

Code:
itotaldaily = ComputeDailyCost(iDays, iDailyCost) 
itotalmile = ComputeMileCost(iDays, iDailyCost)
 
 
Private Function ComputeDailyCost(ByVal a As Integer, ByVal b As Integer)
ComputeDailyCost = a * b
End Function
 
Private Function ComputeMileCost(ByVal a As Integer, ByVal b As Integer)
ComputeMileCost = a * b
End Function
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  #3  
Old April 29th, 2005, 12:21 AM
Kudo_Shiho Kudo_Shiho is offline
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Quote:
Originally Posted by Marc Van Beeume
I'm not a dot net but a VB6 programmer. According to what i know the code should be as follows in VB6. The name of the variable that returns the value is the same as the name of the function. No need to declare a supplemental variable.

Code:
itotaldaily = ComputeDailyCost(iDays, iDailyCost) 
 itotalmile = ComputeMileCost(iDays, iDailyCost)
  
  
 Private Function ComputeDailyCost(ByVal a As Integer, ByVal b As Integer)
 ComputeDailyCost = a * b
 End Function
  
 Private Function ComputeMileCost(ByVal a As Integer, ByVal b As Integer)
 ComputeMileCost = a * b
 End Function


Thank you very much for your help
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Old April 29th, 2005, 05:59 AM
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News to me...

In VB.Net I always use the "Return" keyword.
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  #5  
Old April 29th, 2005, 07:12 PM
Doug G Doug G is offline
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Marc is correct. VB6 <> VB.Net
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Old April 30th, 2005, 07:02 AM
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Code:
iTotalDaily = ComputeDailyCost(iDays, iDailyCost)
       iTotalMile = ComputeMileCost(iMile, iMileCost)
       
       Private Function ComputeDailyCost(ByVal a As Integer, ByVal b As Integer) As Integer
 
       	Return a * b
       
       End Function
       Private Function ComputeMileCost(ByVal a As Integer, ByVal b As Integer) As Integer
 
       	Return a * b
       
       End Function


Fix'd
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