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Mid(string) function

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  #1  
Old November 3rd, 2004, 09:06 PM
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Mid(string) function
Hi, I am trying to use this function. But the string is a variable, I dont know the length. How to solve this problem. Thanks in advance!!!
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  #2  
Old November 3rd, 2004, 09:33 PM
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So many possible answers, all depending on what specifically you are trying to do.

Can you post some sample input/output cases.
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Old November 3rd, 2004, 11:14 PM
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The data string I receive it through serial com, eg, T30H54L12, then I want to seprate it and pass the value to 3 variable, eg, a=30, b=54, c=12. But the length may not be the same, eg, T224H0L128, the output should be a=224, b=0, c=128, thank you so much!
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  #4  
Old November 3rd, 2004, 11:30 PM
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get the length by len(string)

use a loop and the mid statement to then decipher the text
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Old November 3rd, 2004, 11:57 PM
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Sorry, I still can not figure it out, if I write the code as following, what should be the x, y, z? Because I dont know how long is the data, eg, T45H234L0, but somtimes it is T0H4L9. I hope you understand my question.By the way, what loop are you refering to? Thank you so much!!

string = MSComm1.Input
n=len(string)

tmp = Mid(string, 2, x)
hum = Mid(string, x+3, y)
light = Mid(string, x+3+y, z)
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Old November 4th, 2004, 12:18 AM
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Dim XString AsString

Dim I, N, M AsInteger

Dim tmp, hum, light AsInteger

XString = MSComm.Input

N = Len(XString)

M = 0

For I = 1 To N

If Mid(XString, I, 1) = "H" Then

tmp = Mid(XString, 2, I - 2)

M = I + 1

EndIf

If Mid(XString, I, 1) = "L" Then

hum = Mid(XString, M, I - M)

light = Mid(XString, I + 1, N - I)

EndIf

Next I

MsgBox(tmp)

MsgBox(hum)

MsgBox(light)
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  #7  
Old November 4th, 2004, 01:15 AM
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Thanks a lot!
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